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Among experienced computer experts, Linux is often regarded as the 'swiss army knife' of operating systems. Unfortunately, for nearly everyone else, Linux is viewed as a strange and exotic territory, best navigated by people who wear hats with little propellers on them.

One of the important objectives of escapevelocitypub.com is to make the Linux operating system more accessible to people who are new to computers, while at the same time, taking the new computer user from the level of beginner to 'power user'.

It is the conclusion ofescapevelocitypub.com that the very best way to introduce new users to Linux, while at the same time developing skills vital to becoming truly proficient, is by way of the command line. (After all, you don't have to know much to 'point and click'.)

Escapevelocitypub.com welcomes all questions, comments, and suggestions from both novices and experts alike regarding better ways to introduce and teach Linux to computer users, especially individual computer users.

/*use a key_array to do fibonnici addition on the bi-digital plaintext*/

#include<stdio.h>

char key[12] = {'R', 'V', 'I', 'A', 'M', 'O', 'Q', 'X', 'L', 'T', 'B', '\0'};

int key_arr[24];

int main()
	{

int i;

for(i = 0; i < 12; i++)
	{
		printf("%c", key[i]);
	}
	
	int x = 0;

for(i = 0; i < 11; i++)
	{
			
		
		if((key[i]) == 'A'){
			key_arr[x] = 0;
			key_arr[++x] = 1;}

else if((key[i]) == 'B'){
			key_arr[x] = 0;
			key_arr[++x] = 2;}

else if((key[i]) == 'C'){
			key_arr[x] = 0;
			key_arr[++x] = 3;}

else if((key[i]) == 'D'){
			key_arr[x] = 0;
			key_arr[++x] = 4;}

else if((key[i]) == 'E'){
			key_arr[x] = 0;
			key_arr[++x] = 5;}

else if((key[i]) == 'F'){
			key_arr[x] = 0;
			key_arr[++x] = 6;}

else if((key[i]) == 'G'){
			key_arr[x] = 0;
			key_arr[++x] = 7;}

else if((key[i]) == 'H'){
			key_arr[x] = 0;
			key_arr[++x] = 8;}

else if((key[i]) == 'I'){
			key_arr[x] = 0;
			key_arr[++x] = 9;}
		
		else if((key[i]) == 'J'){
			key_arr[x] = 1;
			key_arr[++x] = 0;}

else if((key[i]) == 'K'){
			key_arr[x] = 1;
			key_arr[++x] = 1;}
	
		else if((key[i]) == 'L'){
			key_arr[x] = 1;
			key_arr[++x] = 2;}

else if((key[i]) == 'M'){
			key_arr[x] = 1;
			key_arr[++x] = 3;}

else if((key[i]) == 'N'){
			key_arr[x] = 1;
			key_arr[++x] = 4;}

else if((key[i]) == 'O'){
			key_arr[x] = 1;
			key_arr[++x] = 5;}

else if((key[i]) == 'P'){
			key_arr[x] = 1;
			key_arr[++x] = 6;}

else if((key[i]) == 'Q'){
			key_arr[x] = 1;
			key_arr[++x] = 7;}

else if((key[i]) == 'R'){
			key_arr[x] = 1;
			key_arr[++x] = 8;}

else if((key[i]) == 'S'){
			key_arr[x] = 1;
			key_arr[++x] = 9;}

else if((key[i]) == 'T'){
			key_arr[x] = 2;
			key_arr[++x] = 0;}
		
		else if((key[i]) == 'U'){
			key_arr[x] = 2;
			key_arr[++x] = 1;}

else if((key[i]) == 'V'){
			key_arr[x] = 2;
			key_arr[++x] = 2;}

else if((key[i]) == 'W'){
			key_arr[x] = 2;
			key_arr[++x] = 3;}

else if((key[i]) == 'X'){
			key_arr[x] = 2;
			key_arr[++x] = 4;}

else if((key[i]) == 'Y'){
			key_arr[x] = 2;
			key_arr[++x] = 5;}

else if((key[i]) == 'Z'){
			key_arr[x] = 2;
			key_arr[++x] = 6;}
			
			x++;
				
		}

printf("\n");

printf("%d\n", key_arr[0]);

for(i = 0; i < 24; i++){

printf("%d", key_arr[i]);

}

printf("\n");

return 0;

}

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